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[SQL : CASE / BETWEEN / INNER JOIN] HackerRank : The Report 본문
[SQL : CASE / BETWEEN / INNER JOIN] HackerRank : The Report
Rmsid01 2021. 3. 13. 18:45The Report
>> 문제
You are given two tables: Students and Grades. Students contains three columns ID, Name and Marks.
Grades contains the following data:
Ketty gives Eve a task to generate a report containing three columns: Name, Grade and Mark. Ketty doesn't want the NAMES of those students who received a grade lower than 8. The report must be in descending order by grade -- i.e. higher grades are entered first. If there is more than one student with the same grade (8-10) assigned to them, order those particular students by their name alphabetically. Finally, if the grade is lower than 8, use "NULL" as their name and list them by their grades in descending order. If there is more than one student with the same grade (1-7) assigned to them, order those particular students by their marks in ascending order.
Write a query to help Eve.
Sample Input
Sample Output
Maria 10 99
Jane 9 81
Julia 9 88
Scarlet 8 78
NULL 7 63
NULL 7 68
Note
Print "NULL" as the name if the grade is less than 8.
Explanation
Consider the following table with the grades assigned to the students:
So, the following students got 8, 9 or 10 grades:
- Maria (grade 10)
- Jane (grade 9)
- Julia (grade 9)
- Scarlet (grade 8)
>> 문제 정리
table : Students / Grades
SELECT : NAME , Grade, Mark
조건 : garde 가 8점 이하인 학생의 이름은 제거
순서 : grade desc
- 8-10 점으로 동점이라면 , name
- 8점보다 낮은 점수에서 동점이면, 이름 : 'NULL' , marks
>> 문제 푼 코드
SELECT CASE
WHEN G.grade > 7 THEN S.NAME
ELSE 'NULL'
END AS NAME
, G.grade
, s.marks
FROM Students S
INNER JOIN Grades g
ON s.Marks between g.min_mark and g.max_mark
ORDER BY Grade DESC, s.name, marks
※ 이 문제의 포인트는 INNER JOIN 조건에 BETWEEN 을 쓸 수 있다는 점이다.
www.hackerrank.com/challenges/the-report/problem?h_r=internal-search